select Users.name, (Professions.profession = 'coder') as is_coderfrom Usersleft join Professions on (Users.profession_id = Professions.id)
If there are no duplicates in Professions table and IDs are stable, just:
select Users.name, (Users.profession_id = 1) as is_coderfrom Users
Alexa was dropped 5000 -> 40000, I'm disappointed.
move to US :)
http://www.imagemagick.org/Usage/resize/
/etc/ssh/sshd_config:
PermitRootLogin no
Let's look on oil price as at 1 december :D
crypto-currency mining, neural networking, cuda/opencl calculations:
http://docs.aws.amazon.com/AWSEC2/latest/UserGuide/using_cluster_computing.html#gpu-instance-families
https://azure.microsoft.com/ru-ru/blog/azure-n-series-preview-availability/
https://cloud.google.com/gpu/
Telegram Bot, Slack?
Amazon EC2 changes the IP after stop-start cycle. It's annoying us but will good for you :D
server {listen 80 default_server;listen [::]:80 default_server ipv6only=on;server_name _;location / {rewrite ^ https://site.ru$request_uri permanent;}}