1064 - You have an error in your SQL syntax помогите исправить

добрый день, есть скрипт который заносит значения в бдя, сейчас выдает ошибку

1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.$this->article->id.'";}','0','1ebbb6aeb6f88e48bfa16269fc830b5d','d7c3743effea45' at line 1 SQL=INSERT INTO art3_payforcontent (`id`, `email`, `articleids`, `payment_amount`, `hashtoemail`, `hashtologin`, `url`, `datetime`, `timelimit`, `paidstatus`) VALUES ('','8@yandex.ru','a:1:{i:0;s:22:"'.$this->article->id.'";}','0','1ebbb6aeb6f88e48bfa16269fc830b5d','d7c3743effea4522f2f441c10ed48072','http://сайт','2014-07-23 11:36:31','1',0)

сам скрипт

<?php

/**

 * @version		$Id: user.php 14401 2010-01-26 14:10:00Z louis $

 * @package		Joomla

 * @subpackage	User

 * @copyright	Copyright (C) 2005 - 2010 Open Source Matters. All rights reserved.

 * @license		GNU/GPL, see LICENSE.php

 * Joomla! is free software. This version may have been modified pursuant to the

 * GNU General Public License, and as distributed it includes or is derivative

 * of works licensed under the GNU General Public License or other free or open

 * source software licenses. See COPYRIGHT.php for copyright notices and

 * details.

 */



// Check to ensure this file is included in Joomla!

defined( '_JEXEC' ) or die( 'Restricted access' );



jimport('joomla.application.component.model');



/**

 * User Component User Model

 *

 * @package		Joomla

 * @subpackage	User

 * @since 1.5

 */

class UsersModelPayforcontent extends JModelLegacy

{

	/**

	 * User id

	 *

	 * @var int

	 */

	var $_id = null;



	/**

	 * Constructor

	 *

	 * @since 1.5

	 */

	function __construct()

	{

		parent::__construct();



		$id = JRequest::getVar('id', 0, '', 'int');

		$this->setId($id);

	}



	function setId($id)

	{

		// Set weblink id and wipe data

		$this->_id		= $id;

		$this->_data	= null;

	}



	function getRegUser($id){

		$db =& JFactory::getDBO();

		$this->setId($id);

		

		$query = 'SELECT * FROM #__payforcontent WHERE id='.$id;

		$db->setQuery( $query );

		$result = $db->loadObject();

	 

	   return $result;

	}

	function getUserByHash($hash){

		$db =& JFactory::getDBO();

		

		

		$query = "SELECT * FROM #__payforcontent WHERE hashtoemail='".$hash."'";

		$db->setQuery( $query );

		$result = $db->loadObject();

		

		$this->setId($result->id);

		

	   return $result;

	}

	

	function updateField($field,$value){

		$db =& JFactory::getDBO();

 

		$query = "UPDATE #__payforcontent SET " . $field . "=" . $value .  " WHERE id=".$this->_id;

		$db->setQuery( $query );

		$result = $db->query();

		if(!$result){

			print_r($db->stderr());

		}

	   return $result;

	}

	function store($data)

	{

		$db =& JFactory::getDBO();

		

		$query = 'INSERT INTO #__payforcontent (`id`, `email`, `articleids`, `payment_amount`, `hashtoemail`, `hashtologin`, `url`, `datetime`, `timelimit`, `paidstatus`) VALUES ';

		$query .= "('','".implode("','",$data)."',0)";

		

		$db->setQuery( $query );

		$result = $db->query();

		if($result){

			$result = $db->insertid();

		}else{

			print_r($db->stderr());

		}

		return $result;

	}



}

?>

Я так понимаю что из-за кавычек, но не как не могу понять где именно исправить эти кавычки в запросе...